A water reservoir is 22 m long, 16 m broad and 10 m high. Find the cost of cementing its floor
and the four walls at the rate of 19 per m².
Answers
Answer:
the water reservoir is 22m long, 16 m broad and 10m high.
it's area of four walls is equal to 2h(l+b).
area of four walls =2 * 10(22+16)
= 2*10*38=760 m².
the cost of cementing is 19 per m².
the cost of four walls cementing
= 19*760
= 14440.
Answer:
Answer:
cost of cementing=21,128 Rupees
Step-by-step explanation:
A water reservoir is 22 M long 16 m broad and 10 M height.
So, it's a cuboid with dimensions
l=22 m
b=16 m
h=10 m
Find the area of cementing:
Area to be cemented= Area of base+ lateral surface area
\begin{gathered} = lb + 2(lh + bh) \\ \\ = 22 \times 16 + 2(22 \times 10 + 16 \times 10) \\ \\ = 352 +2 (220 + 160) \\ \\ = 352 + 2(380) \\ \\ = 352 + 760 \\ \\ = 1112 {m}^{2} \\ \\ \end{gathered}
=lb+2(lh+bh)
=22×16+2(22×10+16×10)
=352+2(220+160)
=352+2(380)
=352+760
=1112m
2
cost of cementing at the rate of 19 Rupees per metre square is
\begin{gathered} = 1112 \times 19 \\ \\ = 21128 \: rupees \\ \\ \end{gathered}
=1112×19
=21128rupees
Hope it helps you.