A water sample containd 100ppm of cacl2 3.2mg/L of Nacl 21.1°fr of Al2O3 claculate total hardness of water
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Answered by
2
Answer:
We can calculate the hardness of given water sample as:
(i) Ca(HCO
3
)
2
≡CaCO
3
162ppm≡100ppm
∴81ppm≡50ppm
(ii) Mg(HCO
3
)
2
≡CaCO
3
146 ppm ≡ 100 ppm
∴73ppm≡50ppm
(iii) CaSO
4
≡CaCO
3
136ppm≡100ppm
∴68ppm≡50ppm
(iv) MgSO
4
≡CaCO
3
120ppm≡100ppm
∴60ppm≡50ppm
The hardness is most commonly expressed as milligrams of calcium carbonate equivalent per litre. Calcium carbonate is the compound in hard water that causes limescale build-up. Soft water generally has less than 50 ppm of calcium carbonate, and hard water has over 200 ppm.
Total degree of hardness of water =50×4=200ppm
Answered by
0
Answer:
amount of cacl2 harness =100 ppm
amount of Nacl hardness= 3.2 mg/lot 3.2 ppm
amount of Al2O3 harness =21.1 °Fr
( 1ppm = 0.1 °Fr )
hence,
21.1°Fr = 211 ppm
Total harness of water = 100+ 3.2 + 211
= 314.2 ppm
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