Chemistry, asked by sk1066756, 2 months ago

A water sample containd 100ppm of cacl2 3.2mg/L of Nacl 21.1°fr of Al2O3 claculate total hardness of water​

Answers

Answered by ss6330405
2

Answer:

We can calculate the hardness of given water sample as:

(i) Ca(HCO

3

)

2

≡CaCO

3

162ppm≡100ppm

∴81ppm≡50ppm

(ii) Mg(HCO

3

)

2

≡CaCO

3

146 ppm ≡ 100 ppm

∴73ppm≡50ppm

(iii) CaSO

4

≡CaCO

3

136ppm≡100ppm

∴68ppm≡50ppm

(iv) MgSO

4

≡CaCO

3

120ppm≡100ppm

∴60ppm≡50ppm

The hardness is most commonly expressed as milligrams of calcium carbonate equivalent per litre. Calcium carbonate is the compound in hard water that causes limescale build-up. Soft water generally has less than 50 ppm of calcium carbonate, and hard water has over 200 ppm.

Total degree of hardness of water =50×4=200ppm

Answered by nida345251
0

Answer:

amount of cacl2 harness =100 ppm

amount of Nacl hardness= 3.2 mg/lot 3.2 ppm

amount of Al2O3 harness =21.1 °Fr

( 1ppm = 0.1 °Fr )

hence,

21.1°Fr = 211 ppm

Total harness of water = 100+ 3.2 + 211

= 314.2 ppm

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