a water sample contains 204 mg of caso4 per liter calculate the hardness in terms of caco3 equivalent
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Given: A water sample contains 204 mg of CaSO4 per liter.
To find: Hardness in terms of CaCO3 equivalent
Solution: Let the mass of CaSO4 be m.
Therefore, m = 204 mg/L
Molar mass of CaSO4(M1)
= Atomic mass of Ca + Atomic mass of sulphur+ 4 × atomic mass of oxygen
= 40 + 32 + 4×16
=136 g/ mol
Molat mass of CaCO3(M2)
= Atomic mass of Ca + Atomic mass of carbon+ 3 × atomic mass of oxygen
= 40 + 12 + 3× 16
= 100 g/mol
Hardness in terms of CaCO3 equivalent
= (given mass of CaSO4/ Molar mass of CaSO4) × Molar mass of CaCO3
= (m/M1) × M2
Putting values:
Hardness
= (204/136) × 100
= 1.5 × 100
= 150 mg/L
Therefore, hardness of water in terms of CaCO3 equivalent is 150 mg/L.
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