Chemistry, asked by REDDY1799, 9 months ago

A water sample contains 73ppm of Mg(HCO3), Weight of slaked lime
required to remove the hardness from water sample in Clark's process will
be
(A)
222 ppm
(B) 333 ppm
(C)
74 ppm
(D)
148ppm
A
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Answers

Answered by Anonymous
0

Answer:

ur answer

option b

hope it helps

Answered by srhvr91
3

Answer:

answer is c 74ppm

Explanation:

we know temporary hardness removed by clark method

equation is

Mg(HCO3)2+2CaCO3-------)2CaCO3 +Mg(OH)2+H2O

so see attachment

hope u understand

Attachments:
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