Chemistry, asked by chouhanbharat5054, 1 year ago

A water sample has ppm level concentration of following anionsF⁻ = 10; SO_4^{2-} = 100; NO_3^- = 50the anion/anions that make/makes the water sample unsuitable for drinking is/are :(1) only NO_3^-(2) both SO_4^{2-} and NO_3^-(3) only F⁻(4) only SO_4^{2-}

Answers

Answered by kmohit
0

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Answered by Anonymous
0

Answer:

Only F

Explanation:

NO-3 The maximum limit of nitrate (NO-3) in drinking water is 50 ppm and its source are majorly fertilizers. lf the maximum limit is increased in water it will cause a syndrome known as methemoglobinemia (blue baby syndrome)

SO2-4 The maximum limit of sulphate (SO2-4 ) according to WHO is 500 pm and its major sources are mainly acid rain and the industries. Excess of SO2-4 is seen to have a laxative effect.

F-  The maximum limit of fluoride (F-) is about 1,5 ppm. The higher concentration of fluoride converts enamel to a more harder fluorapatite. Whereas the concentration below > 2ppm causes a brown mottling of teeth and a higher concentration > 10 ppm is harmful for both bones and teeth.

Thus, the SO2-4 at 100 ppm and NO-3 at 50 ppm in water is suitable for drinking but the concentration of F- 10 ppm makes water unsuitable for drinking.

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