Question

A water sample in analysis give the following results : Ca(HCo3)2 =105ppm, Mg(HCo3)2 = 125ppm, CaSo4 = 75ppm, CaCl2 = 82ppm, MgSo4 = 26ppm. Calculate the temporary hardness and permanent hardness in °Fr.

Answer 1

Answer:

We can calculate the hardness of given water sample as:

(i) Ca(HCO

3

)

2

CaCO3≡CaCO

3

162ppm≡100ppm

∴81ppm≡50ppm

(ii) Mg(HCO

3

)

2

≡CaCO

3

146 ppm ≡ 100 ppm

∴73ppm≡50ppm

(iii) CaSO

4

≡CaCO

3

136ppm≡100ppm

∴68ppm≡50ppm

(iv) MgSO

4

≡CaCO

3

120ppm≡100ppm

∴60ppm≡50ppm

Total degree of hardness of water =50×4=200ppm

Explanation:

jope it will help you