A water sprinkler has a range of 5 meters as shown. The jet of water from the sprinkler sweeps out at an angle of 85° as the nozzle turns. What is the area watered by the sprinkler? Use the value π = 3.14, and round your answer to one decimal place.
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Hey mate !!
Here's the answer !!
We know that,
Area of sector = Ф / 360° × πr²
Here we are given with,
Ф = 85°, r = 5 cm
So substituting in the formula we get,
=> Area of sector = 85 / 360 × 2 × 3.14 × 5
=> Area of sector = 17 / 70 × 31.4
=> Area = 0.24 × 31.4 = 7.536 m²
Rounding off to one decimal we get 7.5 m².
Hope my answer helped !!
Cheers !!
Here's the answer !!
We know that,
Area of sector = Ф / 360° × πr²
Here we are given with,
Ф = 85°, r = 5 cm
So substituting in the formula we get,
=> Area of sector = 85 / 360 × 2 × 3.14 × 5
=> Area of sector = 17 / 70 × 31.4
=> Area = 0.24 × 31.4 = 7.536 m²
Rounding off to one decimal we get 7.5 m².
Hope my answer helped !!
Cheers !!
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