Question

A water tank casts a shadow 21m long. A tree of height 9.5 m casts a shadow 8m long at the same time. The lengths of the shadows are directionally proportional to their heights. Find the height of the tank.

Answer 1

$\mathbb{QUESTION}$

A water tank casts a shadow 21m long. A tree of height 9.5 m casts a shadow 8m long at the same time. The lengths of the shadows are directionally proportional to their heights. Find the height of the tank.

$\mathbb{SOLUTION}$

It says that length of their shadows are directly proportional to their height . Height of tank is not known . But in the second scenario of tree the height and the length of the shadows are known . Since we know that height of object and shadow formed are Directly proportional if anyhow we can find the rate by which height and shadow formed differ then we will be able to find the height of the tank too .

We will find the value of theta first .

$\tan( \theta) = \frac{x}{21} - > eqn1$

$\tan( \theta) = \frac{9.5}{80} - > 2$

Adding both the ran 1 and 2 , we get

$\frac{x}{21} = \frac{95}{80}$

$x \times 80 = 95 \times 21$

$80x = 1995$

$x = \frac{1995}{80}$

$\implies \: x = 24.9375 {\mathcal{(answer)}}$

Answer 2

Answer:

oh my god

Step-by-step explanation:

sorry i cant explain