Math, asked by sandeepmorya2656, 10 months ago

A water tank has a capacity of 1000 litres and has three taps which have a constant filling rate of 10 litres, 15 litres and 20 litres per minute, respectively. If half of the tank is filled by using the first 2 tapes flowing together and the remaining half by using only the third tap, how many minutes are required to fill the water tank?

Answers

Answered by geethasan80gmailcom
1
10+15 =25litres per minute
500litres=500÷25=20minutes

20 litres per hour
500÷20=24
=44 minutes

PLEASE THANK
Answered by Anonymous
1

Answer: 45 minutes

Step-by-step explanation:

The half water containing capacity of that tank is = 1000÷2 = 500 litres.

Now,the first 500 litre is filled by first two taps.

Two taps can fill in one minute = (10+15) = 25 litres.

So,

They can fill 25 litres in = 1 minute

They can fill 1 litre in = 1/25 minute

They can fill 500 litre in = 500/25 minutes = 20 minutes.

Now,

The third tap can fill,

20 litres in = 1 minute

1 litre in = 1/20 minute

500 litres in = 500/20 = 25 minutes

So,

The total required time to completely fill that tank is = 20+25 minutes = 45 minutes (answer)

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