Math, asked by avinsmallo8620, 1 year ago

A water tank has two pipes to fill water in it one of the pipes fills water at the rate of 100 liter per hour the tank is filled by the other pipe in four hour and by both pipes together in 2.4 hours what is the capacity of the tank in liters

Answers

Answered by inhumandrowsey
3

Pipe B fills in = 4 hours

Pipe B fills in 1 hour = 1/4

Both together fills in = 2.4 hours

Both pipe fills in 1 hour = 1/2.4

Pipe A alone fills part of tank in 1 hour = 1/2.4 - 1/4

= (5-3) / 12

= 2/12

= 1/6

So pipe A fills the tank alone in 6 hours.

Pipe A fills 100 liter per hour

So, in 6 hours it will fill 100 x 6 = 600 liters

Hence capacity of tank is 600 liters.

Answered by amourya13
3

Answer:

600 litres

Step-by-step explanation:

Pipe B fills in = 4 hours

Pipe B fills in 1 hour = 1/4

Both together fills in = 2.4 hours

Both pipe fills in 1 hour = 1/2.4

Pipe A alone fills part of tank in 1 hour = 1/2.4 - 1/4

= (5-3) / 12

= 2/12

= 1/6

So pipe A fills the tank alone in 6 hours.

Pipe A fills 100 liter per hour

So, in 6 hours it will fill 100 x 6 = 600 liters

Hence capacity of tank is 600 liters.

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