Question

A water tank is cylindrical in shape and the diameter of its base is 28 m. If it is 7 meter deep, how many kilolitres of water can it hold ?





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Answer 1

refer to the attachment :)

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Answer 2

Question :-

$\bigstar$A water tank is cylindrical in shape and the diameter of its base is 28 m. If it is 7 meter deep, how many kilolitres of water can it hold ?

Given :-

$\bigstar$ The diameter of a base of cylinder is 28.

$\rm \therefore \: radius(r) = \frac{d}{2} = \frac{28}{2} = 14m$

To find :-

$\bigstar$ how many kilolitres of water can it hold ?

Formula :-

$\overline{ \underline{ \boxed{\red{\sf \: volume = \pi \times radius \: of \: cylinder \: \times height \: of \: cylinder}}}}$

SolutiOn :-

by using above formula,

put the values of radius, height and value of π as $\large\frac{22}{7}$

so,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \: \rm{v \: = \frac{22}{7} \times {14}^{2} \times 7}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longrightarrow\rm{v \: = \frac{22}{7} \times {14 \times 2} \times 7}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longrightarrow\rm{v \: = \frac{22}{7} \times 28 \times 7}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longrightarrow\rm {\: \boxed{ \sf \green{ v \: = 4312 {m}^{3} }}}$

Now,

we have to change this into in kg ,

we know that,.

1 m³ = 1000

&

1m³ = 1klg

so ,

4312m³ = 4312 klg

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So the cylinder can hold 4312 kg water.

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