A water tank is filled in 12 hours by water falling from 4 pipes of same diameter. What will be time taken to fill the same water tank when only 3 such pipes are opened at the beginning when the tank is empty?
Answers
Answer:
Answer:
20 hrs.
Explanation:
Given,
4 pipes of same dimensions can fill a water tank in 15 hrs.
If there are 3 pipes instead find how long will it take to fill the tank.
Let's say it will take \boldsymbol xx hrs
Now here, the lesser the pipes the more the time it will take.
Hence it's an inversely proportional.
\therefore \: 4 \times 15 = 3 \times x∴4×15=3×x
Solving for \boldsymbol xx
\implies \: 4 \times 15 = 3 \times x⟹4×15=3×x
\implies \: \dfrac{4 \times 15}{3}= x⟹
3
4×15
=x
\implies \: \dfrac{60}{3}= x⟹
3
60
=x
\implies \: 20 = x⟹20=x
\therefore \boldsymbol{ x = 20}∴x=20
Step-by-step explanation:
hence answer is 20 hrs
hope this will help u army!!
Answer:
4 pipes of same dimensions can fill a water tank in 15 hrs.
If there are 3 pipes instead find how long will it take to fill the tank.
Let's say it will take x hrs
Now here, the lesser the pipes the more the time it will take.
Hence it's an inversely proportional.
.. 4 x 15 = 3 × x
Solving for a
4 x 15 3 = X
4 x 15 = 3 x x 83 60 = x
20 = x
..x = 20
Hence, it will take 20 hrs to fill the water tank.
Step-by-step explanation:
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