A water tank is filled in 3hrs by 3 pipes P,Q & R. The pipe R is thirce as fast as Q and Q is twice as fast as P. How much time will pipe P alone take to the water
tank?
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Step-by-step explanation:
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A tank is filled in 5 hours by three pipes P, Q and R
The pipe R is twice as fast as pipe Q and Q is twice as fast as pipe P.
Let pipe P takes, x hours to fill the rank
Then the speed of filling the tank are:
Pipe P takes x hours,
Pipe Q takes x/2 hours, (twice as fast as P),
Pipe R takes x/4 hours, (twice as fast as Q).
According to statement tank is filled in 5 hours by three pipes P, Q and R. Therefore
x + x/2 + x/4 = 5 hours
(4x + 2x + x) / 4 = 5
7x/4 = 5
Cross multiplication
7x = 20
x = 20/7 hour
Thus, pipe A will fill the tank in 20/7 hours
The filling rate of pipe Q is x/2 = 20/14 = 10/7 hours
The filling rate of pipe R is x/4 = 20/28 = 5/7 hours.
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