Math, asked by rsrajatsingh99, 5 months ago

A water tank is filled in 3hrs by 3 pipes P,Q & R. The pipe R is thirce as fast as Q and Q is twice as fast as P. How much time will pipe P alone take to the water
tank?​

Answers

Answered by jasminesaroya605
0

like that

Step-by-step explanation:

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A tank is filled in 5 hours by three pipes P, Q and R

The pipe R is twice as fast as pipe Q and Q is twice as fast as pipe P.

Let pipe P takes, x hours to fill the rank

Then the speed of filling the tank are:

Pipe P takes x hours,

Pipe Q takes x/2 hours, (twice as fast as P),

Pipe R takes x/4 hours, (twice as fast as Q).

According to statement tank is filled in 5 hours by three pipes P, Q and R. Therefore

x + x/2 + x/4 = 5 hours

(4x + 2x + x) / 4 = 5

7x/4 = 5

Cross multiplication

7x = 20

x = 20/7 hour

Thus, pipe A will fill the tank in 20/7 hours

The filling rate of pipe Q is x/2 = 20/14 = 10/7 hours

The filling rate of pipe R is x/4 = 20/28 = 5/7 hours.

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