Question

A water tank is hemispherical below and cylindrical at the top. If the radius is 12 m and capacity is 3312π cubic metre, the height of the cylindrical portion in metres is: ​

Answer 1

Answer:

Volume of tank=33127 cm3

therefore,

volume of tank=volume of cylindrical

portion+volume of hemispherical portion

= Tr²h + 2/3 =Tr² (2/3r+h)=3312 T

=

=3312n

=12X12(2/3X12+h)=3312

=2/3X12+h=3312/144

=8+h=13

=h=5cm

therefore,

ratio of the surface areas is: CSA of hemispherical portion : CSA of

cylindrical portion 2n rh : 2rr2

h:r

5:12

Step-by-step explanation:

Hope it will help

Answer 2

$\huge\underline\mathfrak{\green{Solution }}$

Volume. V

$= \bold{ \frac{22}{7} \times 12 \times 12( \frac{4}{3} \times 12 + h)}$

$\bold{ 3312 \times \frac{22}{7} }$

$\bold{12 \times 12( \frac{4}{3} \times 12 + h) = 3312}$

$\bold{ \frac{4}{3} \times 12 \: \frac{1}{2} + h = 23 }$

8 + h = 23

h = 23 - 8 = 15m