A water tank of dimensions 11m × 6m × 5m is full of water. The tank is emptied through a pipe ofcross section 33 cm2 in 20 hours. Find the rate of water (in kmph).
Answers
The rate of water is 5kmph
Explanation:
Given:
1. A water tank of dimensions 11m × 6m × 5m is full of water.
2. The tank is emptied through a pipe of cross-section 33 cm2 in 20 hours.
To find:
The rate of water
Solution:
==> Volume of water tank = l×b×h
==> Volume of water tank = 11×6×5
==> Volume of water tank = 66×5
==> Volume of water tank = 330m³
We know that 1m = 0.001
==> 1 m =
==> 1m = 10⁻³km
==> 1m³ = 10⁻³×10⁻³×10⁻³ km³
==> 1m³ = 10⁻⁹ km³
==> Volume of water tank = 330×10⁻⁹km³ ==>1
==> The tank is emptied through pipe of cross-section 33 cm² in 20 hours.
==> Volume of water in 20 hours = 20×v×33cm²
We know that, 1cm = 0.00001
==> 1 m =
==> 1m = 10⁻⁵km
==> 1cm² = 10⁻⁵×10⁻⁵
==> 1cm² = 10⁻¹⁰ km³
==> Volume of water in 20 hours = 20×v×33×10⁻¹⁰ km³ ==>2
Equate equation 1 and 2 to find v
==> 330×10⁻⁹ = 20×v×33×10⁻¹⁰
==> 10×10⁻⁹ = 20×v×10⁻¹⁰
==> 10⁻⁸ = 2×10×v×10⁻¹⁰
==> 10⁻⁸ = 2×v×10⁻⁹
==> 2v = 10⁻⁸ ×10⁹
==> 2v = 10
==> v = 5 kmph
==> The rate of water is 5kmph
Answer:
Step-by-step explanation:
The rate of water is 5kmph
Explanation:
Given:
1. A water tank of dimensions 11m × 6m × 5m is full of water.
2. The tank is emptied through a pipe of cross-section 33 cm2 in 20 hours.
To find:
The rate of water
Solution:
==> Volume of water tank = l×b×h
==> Volume of water tank = 11×6×5
==> Volume of water tank = 66×5
==> Volume of water tank = 330m³
We know that 1m = 0.001
==> 1 m =
==> 1m = 10⁻³km
==> 1m³ = 10⁻³×10⁻³×10⁻³ km³
==> 1m³ = 10⁻⁹ km³
==> Volume of water tank = 330×10⁻⁹km³ ==>1
==> The tank is emptied through pipe of cross-section 33 cm² in 20 hours.
==> Volume of water in 20 hours = 20×v×33cm²
We know that, 1cm = 0.00001
==> 1 m =
==> 1m = 10⁻⁵km
==> 1cm² = 10⁻⁵×10⁻⁵
==> 1cm² = 10⁻¹⁰ km³
==> Volume of water in 20 hours = 20×v×33×10⁻¹⁰ km³ ==>2
Equate equation 1 and 2 to find v
==> 330×10⁻⁹ = 20×v×33×10⁻¹⁰
==> 10×10⁻⁹ = 20×v×10⁻¹⁰
==> 10⁻⁸ = 2×10×v×10⁻¹⁰
==> 10⁻⁸ = 2×v×10⁻⁹
==> 2v = 10⁻⁸ ×10⁹
==> 2v = 10
==> v = 5 kmph
==> The rate of water is 5kmph