Question

A water tanker is in the shape of a cylinder with two hemisphere at its ends ,one on each .the length of tank is 63 m and its width is 21 mfind the surface area is m 2

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Given, Common diameter =2 m

Radius =1 m

Total length of tank =8 m

Length of cylinder =h=8−2(1)=6m

Surface area of the tank

= Surface area of two hemispheres + lateral surface area of the cylinder

=2×2πr

2

+2πrh

=2πr(2r+h)

=2×3.14×1(2×1+6)

=50.26m

2

Cost of painting =50.26×60=Rs.3015.92

∴ Cost of painting the tank is Rs. 3015.92

Answer 2

Step-by-step explanation:

Given, Common diameter =2 m

Radius =1 m

Total length of tank =8 m

Length of cylinder =h=8−2(1)=6m

Surface area of the tank

= Surface area of two hemispheres + lateral surface area of the cylinder

=2×2πr

2

+2πrh

=2πr(2r+h)

=2×3.14×1(2×1+6)

=50.26m

2

Cost of painting =50.26×60=Rs.3015.92

∴ Cost of painting the tank is Rs. 3015.92