Question

A waterfall is 100 m high. How much warmer will the water be after the fall? Assume that all the work gets converted into the heat energy. Take the average value of g to be 980cm s2 . #30points

Answer 1

Answer:

Let M be the mass of the water at height h it has potential energy mgh  J=M/H=mgh/msθ=ghsθ=(10ms−2×100m)/(1000calkg−1°C−1×θ)

4.2=(10×100)/(1000×θ)=1/θ

teperature change=1/4.2=0.23°C

Its temperature will rise upto 0.23 degree celcius.

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