A waterfall is 208m high. What is the temperature difference between the too and the bottom of the waterfall
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Answer: 0.5°C
Using the water height as 208m
Q=m*c*(02-01)
where; (02-01)=change in Temperature
Q
=Force*distance
=mass*acceleration*distance
=m*a*d
Q=m*c*(02-01)
m*a*d=m*c*(02-01)
cancel m from both sides
a*d=c*(02-01)
(02-01)=(a*d) / c
(02-01)=(10*208) / 4200
(02-01)=2080/4200
(02-01)= 0.5°C (answer)
Therefore, the change in Temperature is 0.5°C
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