Question

A watermelon weighs 8.5 kgs. it contains 70% water by weight. however, once left to dry in the hot sun for 3 days, it loses 75% of its water content (by weight). what is the water content (by weight) percentage in the watermelon after it has been dried in sun for 3 days?

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Percentage:

                   Percentage, which is a relative figure used to denote hundredths of any quantity.One percent (symbolized as 1%) is equal to 100 parts; hence, 100 percent denotes the complete amount, and 200 percent designates double the amount specified.

Given:

• watermelon weight=8.5 kgs
• It contains 70% of water.
• After dried and loses 75% of its water content

Find:

                   To find the water content percentage in the watermelon after it has been dried.

Solution:

                   Weight of water in Kg =70*8.5/100 =5.95

                   Now 75%of 5.95 kg is lost.

                   Therefore weight of water remaining    is 25%

                   so, 25% of 5.95 is

                   25*5.95/100= 1.4875

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