Question

A wave executing SHM is expressed by equation y = 7 × 10 ^- 6 sin (800πt- [πx/42.5]) where x and y are in cm and t in seconds. calculate the following: amplitude, frequency, wavelength, wave velocity and phase difference between two particles separated by 17 cm

Answer 1

Explanation:

Given A wave executing SHM is expressed by equation y = 7 × 10 ^- 6 sin (800πt- [πx/42.5]) where x and y are in cm and t in seconds. calculate the following: amplitude, frequency, wavelength, wave velocity and phase difference between two particles separated by 17 cm

• Given y = 7 x 10^-6 sin (800 πt – πx / 42.5)
•      So y = 7 x 10^-6 sin 2π (400 t – x / 85)
• We know that y = A sin 2π (t / T – x / π)
• Where A = amplitude = 7 x 10^-6, λ = wavelength = 85 cm T = time period, f = frequency = 1/T = 400 hz
• Now wave velocity v = f x λ
•                               = 400 x 85
•                               = 34,000 cm / s
• Now path difference = 17 cm
• So phase difference = 2π / λ x path difference
•                                = 2π / 85 x 17
•                               = 2π / 5 rad
•                               = 2π / 5 x 180 / π
•                                = 72 degree

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https://brainly.in/question/13859142