Question

A wave frequency 400hz has a wave velocity of 300m/s.the phase difference between two displacement at certain point t=10^-3

Answer 1

Answer: π/5

Explanation:

Given,

f = 400

Wave velocity = ω/k = 300 m/s

ω = 2πf = 2π×400 = 800π

k = 2π/λ

So,

800π/k = 300

k = 2π/3

2π/λ = 2π/3

=> λ = 3m

Now at t = 10⁻³ s

Distance travelled = Velocity × Time

=> x = vt

= 300m/s × 10⁻³ s

= 0.3 m

Now for phase difference, we have:

ΔΦ = (2π/λ) × Δx

Here, Δx = s = 0.3m

So,

ΔΦ = (2π/3) × 0.3

= π/5

Hope that helps you

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