Question

A wave is introduced into a thin wire held tight at each end. It has an amplitude of 5.6cm, a frequency of 50.0 Hz and a distance of 10.5cm. Determine the time period of such a wave. ​

Answer 1

Answer:

Frequency of the wave = 50hz

We know, T=1/f

So, time period = 1/50 = 0.02sec

Answer 2

$\text{In the given question the following parameters are given:}$

$\text{Amplitude}(A) = 5.6 \; cm$

$\text{Freequency}(f) = 50 \; Hz$

$\text{Wavelength}(\lambda) = 10.5 \; cm$

$\text{We must find the Time Period}(T)$

$\text{We know that }f = \dfrac{1}{T}$

$\implies T = \dfrac{1}{f}$

$\implies T = \dfrac{1}{50}$

$\implies \boxed{T = 0.02 \; s}$