Question

A wave is moving in air with a velocity of 340m/s. Calculate the wavelength if its frequency is 512 vibration/second​

Answer 1

Given :

• Velocity of a wave in air(v)=340m/s

•Frequency(f) =512 vibration /second

To Find :

• The wavelength of the wave =?

Formula :

$\red \bigstar \boxed{ \sf{v = f \lambda}}$

Solution :

• Velocity (v) =340m/s

•Frequency(f) =512 vibration /second

•Wavelength =?

By using Formula :

$\\ \\ \implies \sf \: velocity = frequency \times wavelength \\ \\ \\ \\ \implies \sf \: wavelength ( \lambda) = \frac{velocity(v)}{frequency(f)} \\ \\ \\ \implies \sf \: wavelength( \lambda) = \frac{340}{512} \\ \\ \\ \implies \sf \: \lambda = 0.67m$

• The wavelength of the wire is 0.67m

Answer 2

Step-by-step explanation:

HEY ARYAN IT'S UR I'D

• Velocity (v) =340m/s

•Frequency(f) =512 vibration /second

•Wavelength =?

By using Formula :

velocity = frequency \times wavelength \ wavelength ( \lambda) = \frac{velocity(v)}{frequency(f)} \\ \\ \\ \implies \sf \: wavelength( \lambda) = \frac{340}{512} \\ \\ \\ \implies \sf \: \lambda = 0.67m\end{gathered}

⟹velocity=frequency×wavelength

⟹wavelength(λ)=

frequency(f)

velocity(v)

⟹wavelength(λ)=

512

340

⟹λ=0.67m

• The wavelength of the wire is 0.67m