a wave of frequency 400 hz in air has a speed of 320m/s. find its wavelength. what will be the new wavelength when it enters water in which its speed is 1600m/s?
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Answer:
Frequency of wave is, f=400Hz
Velocity of wave is, v=320ms
−1
The phase difference is, ϕ=90
∘
=
2
π
The wavelength of wave is, λ
λ=
f
v
λ=
400
320
λ=0.8m
Now, the phase difference between two particles in a wave is
2π
ϕ
=
λ
x
where, x is the distance between two particles in a wave.
x=
2π
λϕ
x=
2π
0.8(
2
π
)
x=
4
0.8
=0.2m
x=20cm
Explanation:
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