Question

a wave of Lambda is 0.2 M is propagating at 3 metre per second
find frequency
find time period

plz tell

​

Answer 1

Step-by-step explanation:

We know that

general equation of wave

y(x,t)=Asin(kx−ωt)

comparing this equation with given equation

1) A=0.005m → amplitude

k=80

ω=3

2) λ=

k

2π

=

80

2π

=(

40

π

)m

3) Time period T=

ω

2π

=

3

2π

sec

frequency f=

T

1

=

2π

3

Hz

4) Displacement at x=0.3m

t=20 sec

y=0.005sin(80×0.3−3×20)

=0.005sin(24−60)=0.005sin(−36)

=0.00495m

y=4.9mm.

Answer 2

Answer:

We know that

general equation of wave

y(x,t)=Asin(kx−ωt)

comparing this equation with given equation

1) A=0.005m → amplitude

k=80

ω=3

2) λ=

k

2π

=

80

2π

=(

40

π

)m

3) Time period T=

ω

2π

=

3

2π

sec

frequency f=

T

1

=

2π

3

Hz

4) Displacement at x=0.3m

t=20 sec

y=0.005sin(80×0.3−3×20)

=0.005sin(24−60)=0.005sin(−36)

=0.00495m

y=4.9

Step-by-step explanation: