A wave travels at 330m/s^-1. the wavelength is found to be 2.4m.
Calculate the period of oscillation of a article in the medium transmitting the waves.
The frequency of oscillations of the source transmitting the wave
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Answered by
2
Answer:
Let the no be 10x+y
Y is in ones place and x is in tens place According to question the digit in its ones place is twice that of the no which is in tens
place
So x=2y
If 9 is added to the no then the new no is
10x+y +9
And the digits of sum obtained is reversed
So,
10x+y+9 = 10y + x
10x2y+ y + 9 = 10y + 2y
21y+9 = 12y
21y-12y = -9 9y = -9Y = -1
X= 2y
X= -2
The number is 10x+y
10x-2+-1 = -21
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1
Answer:
thank you for providing answer
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