A weak acid reacts with a strong base , ionisation constant of the weak acid is 10^-4 . Find out equilibrium constant for this reaction is
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Answer:
The equilibrium constant will be 1\times 10^{10}1×10
10
.
Explanation: Dissociation of weak acid is given as:
HA\rightleftharpoons H^++A^-HA⇌H
+
+A
−
K_a=\frac{[H^+][A^-]}{[HA]}=10^{-4}K
a
=
[HA]
[H
+
][A
−
]
=10
−4
.....(1)
Dissociation of water can be written as:
H_2O\rightleftharpoons OH^-+H^+H
2
O⇌OH
−
+H
+
K_w=[H^+][OH^-]K
w
=[H
+
][OH
−
] .....(2)
K_w=10^{-14}K
w
=10
−14
(Constant)
Reaction of strong base (BOH) with weak acid can be written as:
HA+OH^-\rightleftharpoons H_2O+A^-HA+OH
−
⇌H
2
O+A
−
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