A weak base (BOH) with kb=10^-5 is titrated with a strong acid,HCL.At 3/4th of the equivalent point ,ph of the solution is ???
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The reaction is given as:HCl+BOH<=>BCl+H2O
Initial concentration..........1...........1.............0...........0
At 3/4th neutralization,1×1/4..........1×3/4
so,pH=-log10^-5+log(3/4)(1/4)=5.477
Initial concentration..........1...........1.............0...........0
At 3/4th neutralization,1×1/4..........1×3/4
so,pH=-log10^-5+log(3/4)(1/4)=5.477
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