Question

A weak mono basic acid is 0.05%
dissociated in its 0.2
M solution
calculate its dissosociation. constant.​

Answer 1

Dissociation constant, for an acid ,Kₐ

$K_{a} = \frac{C \alpha^2}{1- \alpha}$

C= concentration

α = dissociation constant

α = 0.0005

Since, α is very small, i.e. nearly equal to 1,  (1-α) can be neglected.

$K_{a} = {C \alpha^2}$

Kₐ = 0.2 x ( 0.0005)²

≈ 25 × 10⁻⁸ x 0.2

≈ 5 x 10⁻⁸

(For more accurate answer, you can use 1-0.0005, in which case the answer will be : 5.0025 x 10⁻⁸)

Answer 2

Answer:

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