Question

a wedding cake weighed 8 kg. if 2/5th of its weight was flour, 5/16th was sugar, 1/4th was cream and the rest were nuts .find the weight of nuts
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Answer 1

$\color {red} </p><p>\Large \underline {\underline {Question \: :}}$

A wedding cake weighed 8 kg. If 2/5th of its weight was flour, 5/16th was sugar, 1/4th was cream and the rest were nuts. Find the weight of nuts.

$\color {red} </p><p>\Large \underline {\underline {To \: find \: :}}$

The weight of nuts

$\color {red} </p><p>\Large \underline {\underline {Given \: :}}$

• Weight of cake = 8 kg
• Weight of flour = 2/5 of 8 = 16/5 kg
• Weight of sugar = 5/16 of 8 = 5/2 kg
• Weight of cream = 1/4 of 8 = 2 kg
• Weight of nuts = rest

$\color {red} </p><p>\Large \underline {\underline {Solution\: :}}$

$8 - ( \frac{16}{5} + \frac{5}{2} + 2)$

$8 - ( \frac{32 + 25 + 20}{10} )$

$8 - \frac{77}{10}$

$\frac{80 - 77}{10}$

$= \frac{3}{10}$

$\implies$ Hence, the weight of nuts is 3/10 kg which is 300 grams.

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Answer 2

Answer:

8kg - (16/5+5/2+2)

8kg-(32+25+20/20)

8kg=77/10

80-77/10

=3/10

hence the eight of nut is 3/10 kg which is 300 grame