A weiere start from rest at the top of sky slop and down hill find the skier sheed after her elegation 10 m assuming no work is done by friction of air residence
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According to question, the situation is shown in the figure.
For a sufficiently safe-horizontal displacement ΔS can be considered straight. If the corresponding length of path element is ΔL, the friction force is given by μ
mg
ΔL
ΔS
and the work done by the friction force equals force times displacement.
μ
mg
ΔL
ΔS
ΔL=μ
mg
ΔS
Adding up, we find that along the whole path the total work done by the friction force is μ
mg
S. By energy conservation this must equals the decrease mgh is potential energy of skier.
Hence, h=μS.
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