Physics, asked by Manjaripandey5810, 1 year ago

a weight lifter lifted a load of 200 kgf to a height of 2.5 m in 5 s. calculate, the work done and the power developed by him . take G = 10N kg-1

Answers

Answered by raimanbala

98

Force =mass ×gravity

F=200×10

=200N

Work done =d×f

2.5×2000=5000joule

The power developed by him

Power=w÷time taken

P=5000÷5=1000watt

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