A weight Mg is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. The minimum tension required to completely straighten the rope is a) Mg/2 b)Mg cos theta c) 2Mg cos theta d)infinitely large
Answers
Answered by
281
Formula is Mg = 2T sin(theta)
T = Mg/2 sin theta
Given, Rope is no longer horizontal so, theta = 0
so, T = Mg/2 sin(0)
= Mg/2 * 0
= Infinite
So option (D) is the answer.
Hope this helps!
T = Mg/2 sin theta
Given, Rope is no longer horizontal so, theta = 0
so, T = Mg/2 sin(0)
= Mg/2 * 0
= Infinite
So option (D) is the answer.
Hope this helps!
Answered by
27
Answer:
the tension is infinitely large
Explanation:
the angle is 0
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