Question

A weight of 2 kN is placed on an inclined plane. The inclination of the plane
with the horizontal is 30°. What is the component of weight (a) perpendicular
to the plane and (b) parallel to the plane.​

Answer 1

Answer:

Refer to the attachment .

Here mg = 100N

∅ = 30°

The component of force parallel to the plain will be mgsin∅ or 100×1/2 => 50N

The component perpendicular to the plane is Mgcos∅ => 100×√3/2 = 50√3 .