Question

A weight of 290 N and another of 200 N are suspended by a rope on either side of a frictionless pulley.
The acceleration of the system is:
1) 1 m/sec2
2) 1.5 m/sec2
3) 1.8 m/sec2
4) 2.5m/sec2​

Answer 1

Answer:

I just 2.5 mm seconds to the answer for the question and answer

Answer 2

Answer:

In terms of weights, common acceleration

a=

w

1

+w

2

w

1

−w

2

g=

490

90

×9.8=1.8

Since all units are same, we do not care about the units of the calculated quantity, though there is hardly any problem in it.