Question

A weight of 5N move along a horizontal surface 100m long and the co efficient between the body and surface is 0.4 then the work done is​

Answer 1

Given :-

Weight of body = F = 5 N.

Distance travelled = S = 100 m

Here in this question we will find work done by horizontal force as well as work done by Frictional force then we will find net force acting on the body.

Work done by horizontal force,

${W}_{H}$ = F•S

${W}_{H}$ = 500 J

Again,

Work done by Frictional force,

${W}_{f}$ = F•S•μ

${W}_{f}$ = 200 J

Now,

Net work done,

${W}_{net}={W}_{H}-{W}_{f}$

${W}_{net} = (500-200)J$

${W}_{net} = 300J$