Question

A weight of 900 newton is supported by chains of informative and 3 metre respectively detrrmine tensions in each chain​

Answer 1

Answer:

the diagram is on photo click here to view it

Explanation:

We first draw a force diagram that shows the forces acting on the child-seat system and apply Newton’s second law to solve the problem. The child’s path is an arc of a circle, since the top ends of the chains are fixed. Then at the lowest point the child’s motion is changing in direction: He moves with centripetal acceleration even as his speed is not changing and his tangential

acceleration is zero.

(a) Below figure shows that the only forces acting on the system of child + seat are the tensions in the two chains and the weight of the boy:

∑F=Fnet=2T−mg=ma=rmv2

with

Fnet=2T−mg=2(350N)−(40.0kg)(9.80m/s2)=308N

solving for v gives,

v=mFnetr=40.0kg(308N)(3.00m)=4.81m/s

(b) The normal force from the seat on the child accelerates the child in the same way that the total tension in the chain accelerates the child-seat system. Therefore, n=2T=700N

hope it's helpful