A weightless rod is acted upon by upward parallel force of 2N and 4N at ends A and B respectively the total length of rod AB=3m to keep rod in equilibrium a force of 6N should act in ..
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forces acting at A and B are 2N and 4N in upward direction.
So resistive force = 2+4 = 6N And it should act in downward direction.
Let it acts at a distance L.from B
For equilibrium, total moment should be 0. find moment around point B.
moment = 2×3 - 6×L + 4×0 = 0
=> 6 - 6L = 0
=> L = 1m
Distance of the force from end B is 1m
Answer is D. BD = 1m
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the correct
answer is D 1m
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