Question

A weightless rod of length 2 l carries two equal masses m, one secured at lower end A and the other at the middle of the rod B. The road can rotate in vertical plan about a fixed horizontal axis passing through C. What horizontal velocity must be imparted to the mass at A so that it just completes the vertical circle

Answer 1

Answer:

va=4√35Lg

Explanation:

12mv2a+12mv2b=2Lmg+4Lmg

va2L=vbL⇒va=2vb

and substituting

12mv2a+12m(va2)2=6Lmg

and finally

va=4√35Lg