Question

A weightless spring which has a force constant oscillates with frequency n when a mass m is suspended from
it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will
now become
(A)n
(B) 2n
(C) n/2
(D) n(2)2​

Answer 1

Answer:

D is the answerbgfhshbssj

Answer 2

Since time period remains same in both cases, frequency is also same.

Correct option is (A).

Explanation:

Time period of oscillation of a body of mass "m" suspended by a spring is

T = 2π  √ m / k

On cutting spring in two equal parts, the length of each part will remain half and the force constant will be doubled (2k).

Therefore,

T = 2π √ 2m / 2k = f

Since time period remains same in both cases, frequency is also same.