A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your answer to the nearest whole number.
Answers
Explanation:
The Gravitationa potential energy of the mass (PEG) is given by:
U=mghU=mgh
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)
In this problem, m=250 kgm=250kg and h=0.5 mh=0.5m , therefore the gravitational potential energy of the mass is:
U=mgh=(250 kg)(9.8 m/s^2)(0.5 m)=1225 JU=mgh=(250kg)(9.8m/s
2
)(0.5m)=1225J
Given: A weightlifter lifts a 250-kg mass 0.5 meters above his head. g = 9.8 m/s^2
To find: Gravitational potential energy of the spring
Explanation: Gravitational potential energy is the energy a body has due to gravity acting on it. The more the height, higher is the gravitational potential energy.
Let mass of the body be m and height of the object be h.
Then,
m=250 kg
h= 0.5 m
The formula for gravitational potential energy (U)
= mgh
= 250 × 9.8 × 0.5
= 1225 J
The gravitational potential energy of the mass is 1225 J.