Question

A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your answer to the nearest whole number.

Answer 1

Explanation:

The Gravitationa potential energy of the mass (PEG) is given by:

U=mghU=mgh

where

m is the mass

g is the gravitational acceleration

h is the heigth of the mass above the reference level (the ground)

In this problem, m=250 kgm=250kg and h=0.5 mh=0.5m , therefore the gravitational potential energy of the mass is:

U=mgh=(250 kg)(9.8 m/s^2)(0.5 m)=1225 JU=mgh=(250kg)(9.8m/s

2

)(0.5m)=1225J

Answer 2

Given: A weightlifter lifts a 250-kg mass 0.5 meters above his head. g = 9.8 m/s^2

To find: Gravitational potential energy of the spring

Explanation: Gravitational potential energy is the energy a body has due to gravity acting on it. The more the height, higher is the gravitational potential energy.

Let mass of the body be m and height of the object be h.

Then,

m=250 kg

h= 0.5 m

The formula for gravitational potential energy (U)

= mgh

= 250 × 9.8 × 0.5

= 1225 J

The gravitational potential energy of the mass is 1225 J.