A weighty man lift 300kg weight within 3 second time at 2 meter distance from ground.What is the power he will give to it
Answers
Answered by
3
ANSWER :-
P=W/t
w = mgh
w = 300*10*2=6000N
Therefore,
Power = 6000/2=3000J.
P = 3000J
PLEASE MARK AS BRAINLIEST
P=W/t
w = mgh
w = 300*10*2=6000N
Therefore,
Power = 6000/2=3000J.
P = 3000J
PLEASE MARK AS BRAINLIEST
Answered by
0
Given:m=300kg
T=3sec
H=2m
Power=mgh/t
300×9.8×2/3
=1960watt
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