Math, asked by vandiadevan, 1 year ago

A Welfare Association has a sports club where 30% of the members play cricket, 28 % play
volleyball, 22% play badminton and the rest play indoor games. If 30 member play indoor
games.
(i) How many members are there in the sports club?
(ii) How many play cricket, volleyball and badminton?

Answers

Answered by umangparmar
13

Answer:

there are 150 people in the sports club.

there are 42 play volleyball

there are 33 play badminton

there are 45 play cricket

and rest of 30 plays indoor games

Answered by windyyork
14

Answer: (i) 150, (ii) 45,42,33 respectively.

Step-by-step explanation:

Since we have given that

Percent of members play cricket = 30%

Percent of members play volleyball = 28%

Percent of members play badminton = 22%

So, remaining percent of members who play indoor games is given by

100\%-(30\%+28\%+22\%)\\\\=100\%-80\%\\\\=20\%

Number of member who play indoor games = 30

So, According to question, it becomes,

\dfrac{20}{100}\times x=30\\\\0.2x=30\\\\x=\dfrac{30}{0.2}\\\\x=150

(i) there are 150 members in the sports club.

(ii) Number of member who play cricket is given by

0.3\times 150\\\\=45

Number of members who play volleyball is given by

0.28\times 150\\\\=42

Number of members who play badminton is given by

0.22\times 150\\\\=33

Hence, (i) 150, (ii) 45,42,33 respectively.

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