Question

A well 10m inside diameter is dug 14m deep. Earth taken out of it is spread all around to a width of 5m to form an embankment. Find the height of embankment.

Answer 1

Answer:

h=5m

HOPE THIS HELPS.........

Answer 2

AnswEr:

We have,

Volume of the earth dug out = πr²h m³ = 22/5 * 5 * 5 * 14 m³ = 1100 m³

Area of the embankment (shaded region) = π (R² - r²)

$\implies$ Area of the embankment (shAded region) = π (10² - 5²) m² = 22/7 * 75 m²

Let h be the height of the embankment. Then,

Volume of the hollow cylinder = Volume of earth dugout

$\leadsto \sf \: \: \pi( {r}^{2} - {r}^{2})h = 1100 \\ \\ \leadsto \sf \frac{22}{7} (100 - 25) \times h = 1100 \\ \\ \leadsto \sf \: h = \frac{1100 \times 7}{22 \times 75} m = \frac{14}{3} m = 4.66 \\ \\ \therefore \tt \: height \: of \: the \: embankment \: = \frac{volume \: of \: earth \: dugout}{area \: of \: embankment} \\ \\ \implies \tt \: height \: of \: the \: embankment \: = \frac{1100}{ \frac{22}{7} \times 75 } \\ \\ = \tt \: \frac{7 \times 1100}{22 \times 75} = 4.66 \: m$