a well 14 m deep is 2m in radius . find the cost of cementing the inner curved surface at the rate of ₹2per sq.m.
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Answered by
87
depth of well(h) = 14m
radius of well(r) = 2m
Inner surface area of well(like a cylinder) = 2πrh
surface area= 2×22/7 × 2×14 = 176 m2
cost of cementing = ₹2 per m2
total Cost = 176×2 = ₹352
radius of well(r) = 2m
Inner surface area of well(like a cylinder) = 2πrh
surface area= 2×22/7 × 2×14 = 176 m2
cost of cementing = ₹2 per m2
total Cost = 176×2 = ₹352
pragti1:
plz you explain full solution this sum
Answered by
75
Hi,
We know that a well is in th e form of a cylinder.
Here, we have to cement the inner curved surface area. So, we will use curved surface area of cylinder formula.
CSA of Cylinder = 2πrh
= 2 X 22/7 X 14 X 2
= 2 X 22 X 2 X 2
= 176 m².
Hence, the curved surface area is 176 m².
The cost of cementing is Rs. 2/m².
So, cost of cementing 176 m² area is
= 176 X 2
= Rs. 352
Hence, the cost of cementing the inner curved surface at the rate of ₹2per sq.m. is Rs. 352.
#Rehan Ahmad XLX
#Brainly Star
We know that a well is in th e form of a cylinder.
Here, we have to cement the inner curved surface area. So, we will use curved surface area of cylinder formula.
CSA of Cylinder = 2πrh
= 2 X 22/7 X 14 X 2
= 2 X 22 X 2 X 2
= 176 m².
Hence, the curved surface area is 176 m².
The cost of cementing is Rs. 2/m².
So, cost of cementing 176 m² area is
= 176 X 2
= Rs. 352
Hence, the cost of cementing the inner curved surface at the rate of ₹2per sq.m. is Rs. 352.
#Rehan Ahmad XLX
#Brainly Star
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