A well 14 m inside diameter is dug 15 deep . Earth taken out is spread all around to a width of 7 m to form an embankment. Find the height of the embankment .
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5
Answer:
the height of the embankment =5m
Explanation:
volume of earth taken out = πr^2d
=22/7x(7)^2x15
=2310 m^3
volume of embankment = base area x height
= (π(r+7)^2-πr^2)height
r=7 m
both volumes will be equal
2310 = (22/7x14^2 - 22/7x7^2)xheight
2310 =462xheight
height = 5m
karan7830:
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Answered by
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⇛Volume of the earth dug out
= π r^2 h
⇛22 / 7 ×( 14 / 2 ) ^ 2 × 15 m ^ 3 = 2310 m ^ 3 .
⇛Area of the embankment ( Shaded portion) = π ( R^2 - r ^ 2 )
⇛22 / 7 [ ( 14 )^ 2 - ( 7 ) ^ 2 ] = 22 / 7 ( 196- 49) = 462 m ^ 2
⇛Height of the embankment = Volume of the earth dug out / Area of the embankment = 2310 / 462 = 5 m.
⇛Hence,
Height of the embankment
= 5 m.
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