Question

a well 30 m long, 20 m wide and 12m deep is dug in a rectangular field of lenght 588m and breadth 50m. the earth sondugbout is spread evenly on thr remainning part of the field. find tge height ofvtge felield raised by it​

Answer 1

Answer:

0.25m.

Step-by-step explanation:

Dimension of the well is 30 m long, 20 m wide and 12 m deep.

Therefore volume of soil removed = 30×20×12 cq m. = 7200 meter cube.

Now, surface area of field - surface area of well = (588×50) -(30×20) = 29400- 600= 28800 square meter.

Let the height be X.

Therefore,

28800×X = 7200.

X = 7200/28800 = 0.25 m.