Question

a well 30m long, 20m wide and 12m deep is dug in a rectangular field of length 588m and breadth 50m. the earth so dug out is spread evenly on the remaining part of the field. find the height of the field raised by it​

Answer 1

❒ $\:\: \underline{\underline{\bf{\large\mathfrak\red{~~Solution~~}}}}$

the volume of the mud =the volume of the well

=(30×20×12)m³

=7200m³

now....

there will be 4 portions on each each side of the well ..of equal length and breadth and the mud will be spread on these 4 portions having same height...

len

i.e.,the area of the remaining portions is...

=[(58×50)-(30×20)]m²

=[2900-600]m²

=2300m²

∴therefore the height of the mud will be....

=(7200/2300)m

≈3.13 m

✌✌$:\: \underline{\underline{\bf{\large\mathfrak{~hope ~this ~help~you~~}}}}$✌

Answer 2

given answer was having a calculation mistake of writing 588 as 58 , so I am uploading this solution page

height of the field will be raised by 25 cm