Question

a well dug 20 m deep and it has diameter the earth which is dug out is spread evenly on a rectangular plot 22 m long and 14 m borad what is the height of platform form

Answer 1

Volume of the earth dug out = 22/7 x 7/2 x 7/2 x 20

= 770

Area of the rectangular field = 22 x 14

= 308

Volume = area x height

Height = Volume/Area

= 770/308

= 2.5m

Answer 2

⇒ Given:- Height (h) of well :- 20m

Diameter (d) :- 7 m

Radius (r) :- 7/2 m

Volume of earth platform :- 22 m by 14m

⇒ To find :- Height of the platform:- ?

⇒ Solution:-

Volume of cylinder of radius 7/2 m and height 20 m

Volume of cylinder :- π(r^2)(h)

= 22/7×(7/2^2)×20 m^3

= 770 m^3

Let the height raised by 22 m × 14 m platform be equal to h metres

Therefore,

Volume of the earth in platform = Volume of the earth taken out of the well

22 × 14 × h = 770

h = 770/22 × 14 m

h = 5/2 m

h = 2.5 m

Hence , the height of the platform is 2.5 m.