A well is dug 10m deep and 7m diameter in a corner of a field 20 m long and 15m wide. The earth dug out is spread enenly on the remaining field. Find the rise in the level of the field.
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Answer:
weak in maths don't know
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The rise of the level of the field is approximately 1.47 metre.
Given data :
Depth of the well = 10 m
Diameter of the well = 7 m
Dimension of the field = 20 m × 15 m
So,
The radius of the well = 7/2 m
Volume of the well = π × (7/2)² ×10 = 22/7 × 49/4 ×10 = 22× 7/4 ×10 = 11 × 7/2 × 10 = 77/2 ×10 = 38.5×10 = 385 m³
So,the area of the field = 20×15 = 300 m²
Surface area of the well = π×(7/2)² = 38.5 m²
Now,the well was made inside the field.
The actual area of the field = (Area of the field - Surface area of the well) = (300-38.5) = 261.5 m²
Let,the level of rise = x m
So,
The area of the field × Level of rise = Total mud volume
Now,
261.5 × x = 385
x = 385/261.5
x = 1.47 (answer)
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