Math, asked by krantHi7224, 11 months ago

A well is dug 10m deep and 7m diameter in a corner of a field 20 m long and 15m wide. The earth dug out is spread enenly on the remaining field. Find the rise in the level of the field.

Answers

Answered by ParkJimineefangirl
1

Answer:

weak in maths don't know

Answered by Anonymous
2

The rise of the level of the field is approximately 1.47 metre.

Given data :

Depth of the well = 10 m

Diameter of the well = 7 m

Dimension of the field = 20 m × 15 m

So,

The radius of the well = 7/2 m

Volume of the well = π × (7/2)² ×10 = 22/7 × 49/4 ×10 = 22× 7/4 ×10 = 11 × 7/2 × 10 = 77/2 ×10 = 38.5×10 = 385 m³

So,the area of the field = 20×15 = 300 m²

Surface area of the well = π×(7/2)² = 38.5 m²

Now,the well was made inside the field.

The actual area of the field = (Area of the field - Surface area of the well) = (300-38.5) = 261.5 m²

Let,the level of rise = x m

So,

The area of the field × Level of rise = Total mud volume

Now,

261.5 × x = 385

x = 385/261.5

x = 1.47 (answer)

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